PARKER HYDRAULIC CYLINDER Bore (Cylinder Diameter): 125 mm Stroke (Extension Length): 300 mm 

Parker Max 350 Hydraulic Cylinder

1. General Description

The Parker Max 350 hydraulic cylinder is a highly reliable component designed for applications requiring excellent performance and high-pressure resistance. Parker Hannifin is known for producing high-quality hydraulic cylinders, and this model is no exception, offering durability and precision.

2. Materials and Construction

• Tubing : Made of high-strength steel (usually carbon steel or stainless steel) to ensure strength and resistance to high pressures.
• Stem : Stainless steel or treated steel to improve corrosion and wear resistance.
• Seals : Elastomeric materials such as nitrile, fluorocarbons or polyurethane, designed to withstand extreme temperatures and aggressive hydraulic fluids.
• Headers and Flanges : Cast or machined steel for stability and support, treated for long life.

3. Measurements and Dimensions

• Bore (Cylinder Diameter) : 125 mm
• Stroke (Extension Length) : 300 mm
• External Dimensions : External dimensions vary depending on the cylinder specification, but a typical configuration would include the cylinder OD and the dimensions of the end caps and flanges.

4. Mechanical Characteristics

• Maximum Working Pressure : 350 bar (35 MPa)

• Pushing Force : F=A×PF = A \times P $F$ $=$ $A$ $\times$ $P$ Where:

  • FF $F$ is the force (Newton)
  • AA $A$ is the area of ​​the cylinder (m²)
  • PP $P$ is the pressure (Pa)

  Area calculation: A=π×(D2)2A = \pi \times \left(\frac{D}{2}\right)^2 $A$ $=$ $\pi$ $\times$ $($ 2 D ​) 2 For a 125 mm bore: A=π×(0.1252)2≈0.0123 m2A = \pi \times \left(\frac{0.125}{2}\right)^2 \approx 0.0123 \, m^2 $A$ $=$ $\pi$ $\times$ $($ 2 0.125 ​) 2 $\approx$ $0.0123$ $m$ 2

  Force calculation: F=0.0123 m2×35000000 Pa=430,500 NF = 0.0123 \, m^2 \times 35000000 \, Pa = 430,500 \, N $F$ $=$ $0.0123$ $m$ 2 $\times$ $35000000$ $P$ $a$ $=$ $430$ $,$ $500$ $N$

• Extension/Retraction Speed : Varies depending on fluid flow rate and cylinder configuration.

5. Sectors of Use

• Manufacturing Industry : Used in machine tools, presses and automation systems.
• Energy and Oil Sector : Suitable for drilling and handling applications.
• Construction Industry : Used in construction and material handling equipment.
• Automation Sector : For actuators and industrial control systems.

6. Advantages of Stock Purchase

• Immediate Availability : Reduces downtime and improves operational efficiency.
• Competitive Prices : Buying in bulk often allows you to obtain more favorable economic conditions than special orders.
• Lower Risk of Outages : Ensures operational continuity without delays due to component shortages.

7. Brand and Manufacturer

Parker Hannifin Corporation is a leading manufacturer of motion and control components and systems. Founded in 1917, Parker is known for the innovation, reliability, and quality of its products. Their expertise in the design and manufacturing of hydraulic cylinders ensures high-performance solutions suitable for a wide range of industrial applications.

8. Calculating Power at Different Pressures

The power required to operate the cylinder can be calculated with the formula: P=F×vP = F \times v $P$ $=$ $F$ $\times$ $v$ where:

• PP $P$ is the power (Watt)
• FF $F$ is the force (Newton)
• vv $v$ is the speed of the cylinder (m/s)

Assuming an extension velocity of 0.1 m/s: $N$ ×0.1 m/s=43,050 WP = 430,500 \, N \times 0.1 \, m/s = 43,050 \, W $P$ $=$ $\mathrm{430,500}$ $N$ $\times$ $0.1$ $m$ $/$ $s$ $=$ $\mathrm{43,050}$ $W$ $($ $about$ $43$ kW)

Conclusion

The Parker Max 350 hydraulic cylinder is a high-quality component that offers superior performance and durability in demanding industrial environments. Its robust construction and high specifications make it an ideal choice for applications requiring high reliability and durability. Buying it in stock offers significant advantages in terms of availability and cost, ensuring greater operational efficiency.